Solve algebraically: 6a+3b=24, 3a-b=7
Equation 1 : 6a+3b=24Equation 2: 3a-b=7
Rearrange equation 2 to make b the subject:add b to both sides : 3a=7+bminus 7 from both sides: 3a-7=b
Substitute this into Equation 1 : 6a + 3(3a-7)=24
Multiply out the bracket: 6a + 9a - 21 = 24
Simplify:add the a terms together: 15a - 21=24add 21 to both sides: 15a=45divide by 15: a=3
Sub into Equation 2:3(3)-b=7multiply out bracket: 9-b=7add b to both sides: 9=7+bminus 7 from both sides: 2=b
Answer: a=3 b=2
EG
Related Maths GCSE answers
All answers ▸Eleri invests £3700 for 3 years at 2% per annum compound interest. Calculate the value of her investment at the end of the 3 years. Give your answer correct to the nearest penny.
How do i solve simultaneous equations?
How do i solve quadratic equations?
Solve the simultaneous equation by elimination: 3x + y = 11 and 5x + y = 4