Differentiate y=(x^2 + 2x)cos(3x)

Here we need to use the product rule in order to differentiate as we have two functions involved that are being multiplied together. Therefore we use the formula:dy/dx = u dv/dx + v du/dxFirst let u=(x^2 + 2x) and v=cos(3x)Therefore du/dx = 2x + 2 and dv/dx= -3sin(3x) (using chain rule)Next plug the values into the formula to get:dy/dx = (x^2 + 2x)(-3sin(3x)) + cos(3x)(2x + 2)

KB
Answered by Katie B. Maths tutor

3364 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the straight line perpendicular to 3x+5y+6=0 that passes through (3,4)


Given that y = (( 4x + 1 )^3)sin(2x), find dy/dx.


Integrate by parts x2^x


Solve the following equation for k, giving your answers to 4 decimal places where necessary: 3tan(k)-1=sec^2(k)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences