Differentiate y=(x^2 + 2x)cos(3x)
Here we need to use the product rule in order to differentiate as we have two functions involved that are being multiplied together. Therefore we use the formula:dy/dx = u dv/dx + v du/dxFirst let u=(x^2 + 2x) and v=cos(3x)Therefore du/dx = 2x + 2 and dv/dx= -3sin(3x) (using chain rule)Next plug the values into the formula to get:dy/dx = (x^2 + 2x)(-3sin(3x)) + cos(3x)(2x + 2)
KB
Related Maths A Level answers
All answers ▸Evaluate the indefinite integral when the integrand function is tan(x).
How do I show that (cos^4x - sin^4x) / cos^2x = 1 - tan^2x
Differentiate y=(x-1)^4 with respect to x.
Find the values of the constants a and b for which ax + b is a particular integral of the differential equation 2y' + 5y = 10x. Hence find the general solution of 2y' + 5y = 10x .