Solve the simultaneous equations 2x+3y=17 and 10x-y=5.

In order to solve the simultaneous equations, you should first get rid of one of the unknowns. In this case, one of the ways to do this is to multiply both sides of the first equation by 5 (2x+3y=17 => 10x+15y=85) and then subtract the second equation from the first one in order to get rid of the x: (10x+15y)-(10x-y)=(85)-(5) => 16y=80 => y=5. Having found y, we can substitute for y=5 in the second equation to find x: 10x-5=5 => 10x=10 => x=1. Hence, we get x=1, y=5.

BA

Related Maths GCSE answers

All answers ▸

Kelly is trying to work out the two values of w for which 3w-w^3=2. Her values are 1 and -1. Are her values correct?


How to find the nth term of a quadratic sequence?


Find the coordinates of the point where lines 3x+5=y and 6y+x=11 intersect


y = x^2 + 4x + 7 Find the turning point of the equation by completing the square.