The curve C has the equation: y=3x^2*(x+2)^6 Find dy/dx

To find dy/dx, we must use a combination of the Product Rule and the Chain Rule.
If we let 3x^2=u and (x+2)^6=v, the Product Rule tells us that (uv)' = uv'+vu'
u'=6x, but to find v' we need to use the Chain Rule:
The Chain rule states that d/dx f(g(x)) = f'(g(x))g'(x)
(x+2)^6 can be written in the form f(g(x)) where f(x)=x^6 and g(x)=x+2, it follows that f'(x)=6x^5 and g'(x)=1
We can now see that v'=6(x+2)^5
1
Putting all this together, we find that (uv)'= 3x^26(x+2)^5 + (x+2)^66x
= 18x^2(x+2)^5 + 6x(x+2)^6

SH
Answered by Sam H. Maths tutor

3776 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve the equation sin2x = tanx for 0° ≤ x ≤ 360°


Find the exact value of x from the equation 3^x * e^4x = e^7


How do I do integration by parts?


Find the set of values of x for which x(x-4) > 12


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning