The curve C has the equation: y=3x^2*(x+2)^6 Find dy/dx

To find dy/dx, we must use a combination of the Product Rule and the Chain Rule.
If we let 3x^2=u and (x+2)^6=v, the Product Rule tells us that (uv)' = uv'+vu'
u'=6x, but to find v' we need to use the Chain Rule:
The Chain rule states that d/dx f(g(x)) = f'(g(x))g'(x)
(x+2)^6 can be written in the form f(g(x)) where f(x)=x^6 and g(x)=x+2, it follows that f'(x)=6x^5 and g'(x)=1
We can now see that v'=6(x+2)^5
1
Putting all this together, we find that (uv)'= 3x^26(x+2)^5 + (x+2)^66x
= 18x^2(x+2)^5 + 6x(x+2)^6

SH
Answered by Sam H. Maths tutor

3821 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A ball is thrown from ground level at an angle of 30 degrees from the horizontal with a velocity of 20 m/s. It just clears a wall with a height of 5m, from this calculate the distances that the wall could be from the starting position.


A curve C has the following equation: x^3 + 3y - 4(x^3)*(y^3) a) Show that (1,1) lies on C b) Find dy/dx


Differentiate y=(x^2+5)^7


Find ∫(8x^3+6x^(1/2)-5)dx Give your answer in the simplest form.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning