differentiate y=(3x)/(x^2+6)

using the quotent ruledy/dx= (3(x^2+6)-3x(2x))/(x^2+6)^2dy/dx=3(x^2+6-2x^2)/(x^2+6)^2dy/dx=(18-3x^2)/(x^2+6)^2

MS

Related Maths A Level answers

All answers ▸

If y=cos(3x)cosec(4x), find dy/dx.


I'm confused about differentiation and integration, could you explain these to me?


I always mix up my integration and differentiation. How do i stop this?


Solve the following equation for k, giving your answers to 4 decimal places where necessary: 3tan(k)-1=sec^2(k)