Find the area under the curve -sin(x)+5x+x^2 between the y-axis and the line x=1

integrate the function:sin(x)+5x+x² => cos(x)+2.5x²+(1/3)x³sub in your limits, x=1 and x=0:[cos(x)+2.5x²+(1/3)x³]¹₀find the value for when x=1 (remember to use radians for integrating trig):cos(1)+2.5(1)+(1/3)1 = 3.374then for x=0:cos(0)+0+0 = 1take x=0 answer from x=1:area = 3.374-1=2.374 square units