A curve has equation y = (12x^1/2)-x^3/2
y = 12x1/2 - x3/2
First take the 1/2 power and multiply by the integer in front of the x (so 12 x 1/2 = 6), then minus 1 from the power (1/2 - 1 = -1/2) and replace the power above the x with -1/2. So that makes the first part of the equation = 6x-1/2
Next we do the same to the second part of the equation, we take the 3/2 power and multiply by the integer in front of the x (so -1 x 3/2 = -3/2), then minus 1 from the power (3/2 - 1 = 1/2). So that makes the second part of the equation = (-3/2) x1/2. So putting it together the final answer is dy/dx = 6x-1/2 -(3/2) x1/2
AB
Related Maths A Level answers
All answers ▸A mass of 3kg rests on a rough plane inclined at 60 degrees to the horizontal. The coefficient of friction is 1/5. Find the force P acting parallel to the plane applied to the mass, in order to just prevent motion down the plane.
Express 3cos(theta) + 5sin(theta) in the form Rcos(theta - alpha) where R and alpha are constants, R>0 and 0<alpha<90. Give the exact value of R and the value of alpha to 2dp.
how do I differentiate?
How to draw the inverse of a function ?