Find the tangent to the curve y = x^2 + 3x + 2 that passes through the point (-1,0), sketch the curve and the tangent.

Differentiate to find dy/dx = 3x + 2;at point (-1,0) dy/dx = -1substitute in to y = mx + c, noting m = -1 and the line passes through (-1,0) yields c = -1y = -x - 1, simple to sketch this line.curve sketching, note we already have a zero crossing from the point in the question, find the other zero crossing as (-2,0), sketch a typical x^2 curve passing through the zero crossings and the y intercept at (0,2).