Differentiate f(x) = 14*(x^2)*(e^(x^2))

Differentiate f(x) = 14x2ex^2To approach this problem we first need to realise that f(x) is made up of two simpler functions multiplied together. This tells us that we should use the product rule to solve this (if f(x) = u(x)v(x) then f'(x) = u(x)v'(x) + u'(x)v(x)) Let's say our u(x) is 14x2. Then our u'(x) = 2 * 14 * x2-1 = 28xTherefore our v(x) is ex^2. If we are new to this we could then use the chain rule to solve for v'(x) OR if we are familiar with this form we might see straight away that v'(x) = 2xex^2 . To get our final answer we just follow the product rule definition as above, using the solutions u'(x) and v'(x) that we've just found.

TC

Related Maths A Level answers

All answers ▸

Two particles A and B of mass 2kg and 3kg respectively are moving head on. A is moving at 5m/s and B is moving at 4m/s. After the collision, A rebounds at 4m/s. What is the speed of B and what direction is it moving in?


Given that y= 5x^2 + 2x , find dy/dx


Expand and simplify (3 + 4*root5)(3 - 2*root5)


Why does the product rule for differentiating functions work?