Explain the basics of projectile motion

If the projectile is released at an angle, it will have 2 components: 1. horizontal component of motion and 2. vertical component Horizontally, the projectile is assumed to travel at a constant speed (ie 0 acceleration) because air resistance is assumed to be negligible (so small it is 0)This means that we can use the equation for average speed for horizontal motion, speed=distance/timeVertically, the projectile is assumed to accelerate constantly towards the ground due to gravity, at 9.8 ms^-2. This means we can use the 'SUVAT' equations, which are used specifically for projectiles with constant acceleration. These are: - s=ut+0.5at^2 ; v=u+at ; s=0.5(u+v)(t) ; v^2=u^2+2as.Based upon the knowns and unknowns that you have, you must choose the appropriate equation to use. For example, if we have u,v and t. And we need to find s. Then we must use s=0.5(u+v)(t) because this equation accomodates all 3 knowns + the 1 unknown, so that you are able to rearrange the equation to make the unknown the subject.

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Answered by Aadam Q. Maths tutor

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