Given y = 2x(x^2 – 1)^5, show that dy/dx = g(x)(x^2 – 1)^4 where g(x) is a function to be determined.
y=2x(x2-1)5dy/dx= 2(x2-1)5 + 2x*10x(x2-1)4dy/dx=(x2-1)4(2x2-2+20x2)dy/dx=(x2-1)4(22x2-2)
KS
y=2x(x2-1)5dy/dx= 2(x2-1)5 + 2x*10x(x2-1)4dy/dx=(x2-1)4(2x2-2+20x2)dy/dx=(x2-1)4(22x2-2)
