Solve algebraically the simultaneous equations: 6x=5-2y 12.5=3x+3y

  1. Rearrange both equations into the form ax + by = c. 3x+3y = 12.5 6x +2y = 5. 2) Make either x or y have the same coefficient in each equation. In this case we use x, to do this we multiply the first equation by two to get 6x. The second equation remains the same. 6x + 6y = 25. 6x + 2y =5. 3) We can now solve for y by subtracting equation 2 from equation 1. 4y = 20. y = 5. 4) Substitute y into the equation to find x. 6x + 10 = 5. x = -5/6. 5) Substitute your answers back into the equation to check they are correct. You may use a calculator.
LW
Answered by Laura W. Maths tutor

2940 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise x^2 + 2x - 3


There are only red , blue and purple counters in a bag. The ratio of the number of red counters to the number of blue counters is 3 : 17. If a counter is taken randomly the probability that it is purple is 0.2 Work out the probability for it to be red.


The size of each interior angle of a regular polygon is 11 times the size of each exterior angle. Work out how many sides the polygon has.


Solve 5x-9=26.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning