Solve algebraically the simultaneous equations: 6x=5-2y 12.5=3x+3y

  1. Rearrange both equations into the form ax + by = c. 3x+3y = 12.5 6x +2y = 5. 2) Make either x or y have the same coefficient in each equation. In this case we use x, to do this we multiply the first equation by two to get 6x. The second equation remains the same. 6x + 6y = 25. 6x + 2y =5. 3) We can now solve for y by subtracting equation 2 from equation 1. 4y = 20. y = 5. 4) Substitute y into the equation to find x. 6x + 10 = 5. x = -5/6. 5) Substitute your answers back into the equation to check they are correct. You may use a calculator.
LW
Answered by Laura W. Maths tutor

2901 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

(a) show that 3/10 + 2/15 = 13/30 (b) show that 2 5/8 ÷ 1 1/6 = 2 1/4


A family go into a shop, they buy three sandwiches and two packets of crisps. It costs them £9. Another family buy five sandwiches and six packets of crisps. It costs them £19. How much does two sandwiches and five packets of crisps cost?


Calculate the value of 2^(–3) as a fraction in its simplest form.


The equation of Line 1 is y=2x-2 and the equation of Line 2 is 2y-4x+5=0. Prove that these 2 lines are parallel to each other.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning