Solve the simultaneous equations: 3x-y=13, 2x+y=12

To solve these simultaneous equations we first need to eliminate one variable (the x or the y). For this we will need the coefficients (numbers in front of the variables) to be equal or opposite on one variable in each of the equations. In our question, we can already see the first equation has a +1 in front of the y, and the second equation has a -1 in front of the y. Adding these two equations together gets 5x=25 which is great because the y has been completely eliminated and we can divide both sides of the equation by 5 to get x=5! Substituting this back into our first equation gives (2x5)+y=12. Take 10 off both sides to get y=2, and there we have solved the simultaneous equations for x and y.

ED
Answered by Ellie D. Maths tutor

5105 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve simultaneous equations x + y = 3 and -3x + 5y = 7


For all values of x, f(x) = (x + 1)^2 and g(x) = 2(x-1). Show that gf(x) = 2x(x + 2) and find g^-1(7)


A right angled triangle has two short sides of lengths 5cm and 12cm respectively. What is the length of the third side?


4x^2 + 8x + 3 can be written in the form a(x + b)^2 + c where a, b and c are whole numbers. Work out the values of a, b and c.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning