How do I differentiate (cosx)/x^2

Label function: y=(cosx)/x2Recall quotient rule for functions of form h(x)=f(x)/g(x) given by,h'(x)=(f'(x)g(x)-f(x)g'(x))/(g(x))2Split original equation into f(x)=cosx and g(x)=x2Calculate individual derivatives f'(x)=-sinx and g'(x)=2xThen just plug in the functions into the quotient rule formula to acquire:y'=(-x2sinx-2xcosx)/(x2)2(take a factor of -x out) =-x(xsinx+2cosx)/(x4)(x's cancel out) =-(xsinx+2cosx)/x3

CD
Answered by Caelen D. Maths tutor

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