How do I differentiate (cosx)/x^2

Label function: y=(cosx)/x²Recall quotient rule for functions of form h(x)=f(x)/g(x) given by,h'(x)=(f'(x)g(x)-f(x)g'(x))/(g(x))²Split original equation into f(x)=cosx and g(x)=x²Calculate individual derivatives f'(x)=-sinx and g'(x)=2xThen just plug in the functions into the quotient rule formula to acquire:y'=(-x²sinx-2xcosx)/(x²)²(take a factor of -x out) =-x(xsinx+2cosx)/(x⁴)(x's cancel out) =-(xsinx+2cosx)/x³