how to derive escape velocity
escape volocity is the minimum volocity required for one object toescape the gravitationl feild of another.we find this by equating gravitional potental enegy and the kinetic energy of the object to 1/2 * m * v^2 = GMm/rby simply rearanging to find "v" we find V = (2GM/r)^.5
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All answers ▸I don't understand differentiation. How does it work?
Given the function f(x) = (x^2)sin(x), find f'(x).
Find the surface area of a hand held fan (modeled with negligible depth) with radius 8 cm and a 60 degree angle at the centre
I don't understand how to visualise differentiation, please could you show my an example to allow me to understand what it actually is better?