How can I work out the equation of a line defined by 2 known points?

We know that the equation of a line takes up the slope-intercept form: y = mx + n,where m is the slope and n is the y intercept To work out the equation of the line for our 2 points, we use the point-slope formula: y - y1 = m(x - x1)where m is the slope and x1 and y1 are the coordinates of a point on the line.In our case, we know that A (5, 2) is a point on the line so x1 = 5 and y1 = 2.In order to use the point-slope formula, we also need to work out the slope of the line. We know that the slope has the formula: m = change in y/change in x = yB - yA/ xB - xA,where xA and yA represent the coordinates of point A, in our case, xA = 5 and yA = 2.and, similarly, xB and yB represent the coordinates of point A, in our case, xB = 1 and yB = 6.We substitute the values that we know in the formula above to work out the slope.=> m = 6 - 2/ 1 - 5=> m = 4/-4=> m = -1 We work out the equation of the line by using m, x1 and y1 in the point-slope formula: y - y1 = m(x - x1)y - 2 = -1(x - 5)We simplify this equation, putting it in the form: y = mx + n=> y - 2 = -x + 5=> y = -x + 7 The equation of the line is: y = -x + 7.

DF
Answered by Daria F. Maths tutor

5646 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Simplify the following fraction - Numerator = 2(8-k) + 4(k-1) Denominator = k^2 - 36


Solve 7x+6 > 1+2x


Write 2x^2 + 6x + 6 in the form a(x^2 + b) + c by completing the square.


The equation of the line L1 is y=3x–2. The equation of the line L2 is 3y–9x+5=0. Show that these two lines are parallel.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning