What is y' when y=3xsinx?

In order to differentiate something like y=3xsinx, you need to make use of the product rule. The product rule says that when you have an equation in the form y=f(x)g(x), you can find y' by using the formula y'=f'(x)g(x) + g'(x)f(x).For the equation y=3xsinx, this basically means we can split it into two separate functions of x and differentiate them seperately. In this case we have, for example, that f(x)=3x and g(x)=sinx. So we have that f'(x)=3 and that g'(x)=cosx. By applying the product rule from above [y'=f'(x)g(x) + g'(x)f(x)], we have that y'=3sinx+3xcosx.This works for any y=f(x)g(x), as long as both f(x) and g(x) have valid derivatives.

ES

Related Maths A Level answers

All answers ▸

Express 8/((root3) -1)) in the form a(root3) +b, where a and b are integers.


Differentiate y= (6x^2 - 5)^(3/2) with respect to x


The element of a cone has length L. For what height H (with respect to L) will the volume of the cone be the largest?


Differentiate F(x)=(25+v)/v