Find the equation of the the tangent to the curve y=x^3 - 7x + 3 at the point (1,2)

y_C=x³ - 7x + 3 ------> equation of curve.y_T=mx+c ----------------> equation of tangent, where m is the gradient of the graph and c is the value of the y-intercept (the value of y when x=o)To find m, you must take the differential of curve, and substitute the value of x from (1,2) into it.m=3x² -7, m= 3(1)² -7, m=-4Now, the equation of the tangent looks like y_T=-4x+C.In order to find C, Subsitute the values of the (2,1) in for x and y.2=-4(1)+C2+4=C, C=6Therefore the function of the tangent is y_T=-4x+6