25 cm3 of NaOH was titrated with 0.050 mol dm-3 HCl. NaOH + HCl --> NaCl + H2O. 21.5 cm3 HCl neutralised 25 cm3 NaOH. Concentration of NaOH in mol dm-3?
21.5 cm3 / 1000 = 0.0215 dm3 of HCl. n = cv so (0.050) x (0.0215) = 0.001075 mols of HCl. NaOH + HCl --> NaCl + H2O so there is a 1:1 ratio of reactants to products. Therefore there are 0.001075 mols of NaOH. n = cv so n /v = c. (0.001075) / (0.025) = 0.043 mol dm-3 is the concentration of NaOH
AS
Related Chemistry GCSE answers
All answers ▸Explain which species is oxidised in this reaction: Br2 +2I– 2Br– +I2.
What processes occur throughout the limestone cycle? (3 marks)
Potassium forms an ionic compound with sulfur. Describe what happens when atoms of Potassium react with atoms of sulfur. Give your answer in terms of electron transfer.
What observations would I expect to make if I dropped from magnesium into some hydrochloric acid? What is the balanced chemical equation?