25 cm3 of NaOH was titrated with 0.050 mol dm-3 HCl. NaOH + HCl --> NaCl + H2O. 21.5 cm3 HCl neutralised 25 cm3 NaOH. Concentration of NaOH in mol dm-3?
21.5 cm3 / 1000 = 0.0215 dm3 of HCl. n = cv so (0.050) x (0.0215) = 0.001075 mols of HCl. NaOH + HCl --> NaCl + H2O so there is a 1:1 ratio of reactants to products. Therefore there are 0.001075 mols of NaOH. n = cv so n /v = c. (0.001075) / (0.025) = 0.043 mol dm-3 is the concentration of NaOH
AS
Related Chemistry GCSE answers
All answers ▸How many electrons are in a chloride ion Cl- and how are they arranged in the shells? a periodic table can be used.
During fractional distillation, what are we seperating and how are we seperating them?
How can we calculate product yield using reactants and reaction stoichiometry?
Why does iodine have a higher boiling point than chlorine?