Find the equation of the line perpendicular to the line y= 3x + 5 that passes through the point (-1,4)

Logically work through the problem: 1) Plot all the information that is available so you can visualise the problem better (always encouraged for graphical questions) 2) Understand that the gradient of the perpendicular line is the negative inverse of the gradient of the line, in this case the gradient of the perpendicular line is -1/3 3) Now you have a gradient and a point, which is sufficient information to plot the line, 4 = -1 x -1/3 + c implies c = 13/3 therefore y = -1/3x + 13/3

CC
Answered by Chagall C. Maths tutor

3115 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the straight line perpendicular to 3x+5y+6=0 that passes through (3,4)


write 2(sin^2(x)- cos^2(x)) + 6 sin(x) cos(x) in terms of cos(2x) and sin(2x)


How do I integrate 4x*exp(x^2 - 1) with respect to x?


Find the indefinite integral of sin(2x)(cos^2(x)) with respect to x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences