Differentiate y = ln (3x + 2)
The equation for the derivative of the natural log is dy/dx = f'(x)/f(x) where f(x) = the contents of the natural log, in this case 3x+2. So, to get dy/dx we first need f'(x), the derivative of f(x). This is 3, as the first terms x power decreases to 0, making it equal 3*1 and the constant becomes zero. This means dy/dx 3/3x+2.
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