Find the point(s) of intersection of the curve y=x^2+7x+14 and y=2x+8:
Equate the two graphs:x2+7x+14=2x+8Rearrange to find a single quadratic:x2+5x+6=0Factorize and solve:(x+2)(x+3)x=-2 x=-3Sub x values into one of the original graphs to find y:(-2,4) (-3,2)
I can also provide snapshots of Desmos Graphing Calculator to show what the algebra is actually doing
DM
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