If the functions f and g are defined: f: x--> x/5 + 4 g : x--> 30x + 10. what is x, if fg(x) = x. ?? What would fgf(x) = x^2 be??
You should insert function g into function f. (30x + 10) / 5 + 4 = 0 6x + 2 + 4 = 0 6x + 6 = 0 x = -1
This is a more complex problem:You need to do a similar task but you should do it in steps.gf(x) = 30 (x/5 + 4) + 10gf(x) = 6x + 130fgf(x)= (6x+ 130)/5 +46/5 x + 30
6/5x + 30 = x1/5x = -30x= -150
LM
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