Answers>Maths>A Level>Article

y = 4sin(x)cos(3x) . Evaluate dy/dx at the point x = pi.

By product rule:u = 4sin(x) v = cos(3x)du/dx = 4cos(x) dv/dx = -3sin(3x)dy/dx = u (dv/dx) + v (du/dx)dy/dx = 4sin(x) * -3sin(3x) + cos(3x) * 4cos(x)dy/dx = -12sin(x)sin(3x) + 4cos(x)cos(3x)Evaluate at x = pi . dy/dx = 4.

Answered by Will F. • Maths tutor

4854 Views

See similar Maths A Level tutors

y = 4sin(x)cos(3x) . Evaluate dy/dx at the point x = pi.

Related Maths A Level answers

Consider the function y = x.sin(x); differentiate the function with respect to x

With log base 4, solve log(2x+3) + log(2x+15) = 1 + log(14x+5)

Find the equation of the tangent to the curve y = 4x^2 (x+3)^5 at the point (-1, 128).

Find the equation of the tangent at x=1 for the curve y=(4x^2+1)^3