L is a line parallel to 4x-2y=8. Find the equation of the line if L passes through (4,(38/3))
Since L is parallel to 4x-2y=8, it means that both lines have the same gradient. (Reminder: in y=mx+c, m is the gradient)4x-2y=8, therefore 2y=4x-8, and dividing both sides by 2 results to y=2x-4. Therefore, the gradient of both lines is 2.Hence, line L is in the form y=2x+c. Substituting then our coordinates (4,(38/3)) in the equation of line L will give us the y intercept.(38/3)=2(4)+cso c=14/3. Therefore equation of Line L is y=2x+14/3
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