A particle A of mass 0.1kg is moving at a speed of 1.5m/s to the right. It collides with a particle B of mass 0.3kg moving at a speed of 1.1m/s to the right. Calculate change in momentum of particle A if particle B has a speed of 1.4m/s after collision.
Momentum is conserved during the collision.Momentum = mass x velocityMomentum before = momentum after(mv)P1 + (mv)Q1 = (mv)P2 + (mv)Q2(0.1 x 1.5) + (0.3 x 1.1) = 0.1vP2 + (0.3 x 1.4)vP2 = 0.6m/sChange in momentum of P:(mv)before = 0.1 x 1.5 = 0.15kgm/s(mv)after = 0.1 x 0.6 = 0.06kgm/sΔ(mv) = 0.15 – 0.06 = 0.09kgm/s
JS
Related Maths A Level answers
All answers ▸A curve has the equation y=x^3+2x+15. Find dy/dx.
A curve is described by the equation (x^2)+4xy+(y^2)+27=0. The tangent to the point P, which lies on the curve, is parallel to the x-axis. Given the x-co-ordinate of P is negative, find the co-ordinates of P.
x^2 + y^2 + 10x + 2y - 4xy = 10. Find dy/dx in terms of x and y, fully simplifying your answer.
At x=3, is the polynomial y= (4/3)x^3 -6x^2 + 11 at a maxima or minima?