A particle A of mass 0.1kg is moving at a speed of 1.5m/s to the right. It collides with a particle B of mass 0.3kg moving at a speed of 1.1m/s to the right. Calculate change in momentum of particle A if particle B has a speed of 1.4m/s after collision.

Momentum is conserved during the collision.Momentum = mass x velocityMomentum before = momentum after(mv)P1 + (mv)Q1 = (mv)P2 + (mv)Q2(0.1 x 1.5) + (0.3 x 1.1) = 0.1vP2 + (0.3 x 1.4)vP2 = 0.6m/sChange in momentum of P:(mv)before = 0.1 x 1.5 = 0.15kgm/s(mv)after = 0.1 x 0.6 = 0.06kgm/sΔ(mv) = 0.15 – 0.06 = 0.09kgm/s

JS
Answered by Juliet S. Maths tutor

3676 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the first 4 term of the binomial expansion (2-4x)^5


Find the gradient of the tangent to the line y=(x-2)^2 at the point that it intercepts the y-axis


Integrate 1/(5-2x) for 3≤x≤4


The curve C has a equation y=(2x-3)^5; point P (0.5,-32)lies on that curve. Work out the equation to the tangent to C at point P in the form of y=mx+c


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning