A particle A of mass 0.1kg is moving at a speed of 1.5m/s to the right. It collides with a particle B of mass 0.3kg moving at a speed of 1.1m/s to the right. Calculate change in momentum of particle A if particle B has a speed of 1.4m/s after collision.

Momentum is conserved during the collision.Momentum = mass x velocityMomentum before = momentum after(mv)P1 + (mv)Q1 = (mv)P2 + (mv)Q2(0.1 x 1.5) + (0.3 x 1.1) = 0.1vP2 + (0.3 x 1.4)vP2 = 0.6m/sChange in momentum of P:(mv)before = 0.1 x 1.5 = 0.15kgm/s(mv)after = 0.1 x 0.6 = 0.06kgm/sΔ(mv) = 0.15 – 0.06 = 0.09kgm/s

JS
Answered by Juliet S. Maths tutor

3894 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate ln(x)?


The polynomial p(x) is given by p(x) = x^3 – 5x^2 – 8x + 48 (a) (i) Use the Factor Theorem to show that x + 3 is a factor of p(x). [2 marks] (ii) Express p(x) as a product of three linear factors. [3 marks]


Express asin(x) + bcos(x) in the form Rsin(x+c), where c is a non-zero constant.


Find the derivative of the following function with respect to x. y = 5e^x−2xsin(x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning