Solve the simultaneous equations: 3x + y = -4 and 3x - 4y = 6

First subtract the first equation from the second getting:0 - 5y = 10-5y = 10Then divide both sides by (-5)y = -2Then substitute the y value of (-2) back into the first equation giving:3x + (-2) = -43x = -2x = -2/3And then check by substituting both values into the other equation that you were given.3(-2/3) -4(-2) = -2 +8=6There for the answer is, x=-2/3 and y=-2

LC

Related Maths GCSE answers

All answers ▸

There is a quarter circle with radius 8cm, what is the area of the quarter circle. The answer should be given in terms of pi, units are cm^2.


(4x + 3)/(x + 1) + 2 = 8


Find the minimum value of the quadratic 3x^2-8x+1.


ABCD is a rhombus on a graph. B(7,10). AC: y=7-4x. Find an equation for DB in the form tx+py+r=0 where t,p&r are integers.