differentiate with respect to x: (x^3)(e^x)
because the equation is made up of two functions we can think of them separately when differentiating:f(x)= x^3 f'(x)= 3x^2g(x)= e^x g'(x)= e^xdy/dx= (3x^2e^x)+ (x^3e^x)
JS
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How do I differentiate implicitly?
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