How do you solve inequalities when you have two inequality symbols in the expression, e.g. 4x - 6 < 14 < 3x + 2

So to tackle this question you have to imagine 4x + 6 < 14 < 3x - 2 as two separate inequalities.4x - 6 < 14 and 14 < 3x + 2
This still means the same thing but we have simplified it by looking at them one at a time.
We now solve them for x imagining that the inequality sign < is an equals.So we have:4x - 6 = 144x = 20 (add 6 to both sides)x = 5 (divide by 4)put the inequality sign back in x < 5
14 = 3x + 212=3x4=x4 < x
Combine the two again:
4 < x < 5

AP

Related Maths GCSE answers

All answers ▸

Find dy/dx of y=x^2 + 2x+1


Find the solutions to the quadratic equation x^2-9x+20=0


Solve the simultaneous equations. 2x + y = 18 . x - y = 6


Lisa, Max and Punita share £240 in the ratio 3 : 4 : 8 How much more money than Lisa does Punita get?