25cm3 NaOH was titrated with 0.05mol dm-3 HCl. 21.5m3 of HCl neutralised 25cm3 of NaOH. What is the concentration of NaOH in mol dm-3?
NaOH + HCl --> NaCl + H2O 1 : 1 : 1 moles (mol) = concentration (mol dm-3) x volume (dm3) n(HCl) = 0.05 (mol dm-3) x 21.5/1000 (dm3) = 0.001075 moles (1.075 x 10-3) Using 1:1 molar ratio: n(NaOH) = n(HCl) n(NaOH) = 0.001075 moles concentration (mol dm-3) = moles (mol) / volume (dm3) [NaOH] = 0.001075 (mol) / 0.025 (dm3) = 0.043 mol dm-3
BA
Related Chemistry GCSE answers
All answers ▸c) What does the rate of reaction depend on? (2 marks)
Name the type of reaction that takes place when calcium carbonate is heated strongly?
What is the Lowry and Bronsted definition of acids and bases?
Draw the chemical structures of butane, butene and butyne.