Find the equation of the line tangential to the function f(x) = x^2+ 1/ (x+3) + 1/(x^4) at x =2

Differentiate the function to find the gradient at any point: df/dx = 2x - 1/(x+3)^2 - 4/(x^5)insert the value of 2 into f(x) and df/dx --> df/dx = 3.835, f(2) = 4.2625create the equation of the line by y-ycoord/x- x coord = gradient so y- 4.2625/x-2 = 3.825. We then rearrange this equation to produce an equation of the line in a simpler format