Simplify, leaving your answer as a quadratic: (2x + 3)/(x+4) - (3x - 6) = 4

(2x + 3)/(x+4) - (3x - 6) = 4 Initial equationTimes all terms by (x + 4) (2x + 3) - (3x - 6)(x + 4) = 4 (x + 4)Multiply out the brackets (2x + 3) - (3x2 + 12x - 6x - 24) = 4x + 16Remove from brackets by factoring in the minus sign 2x + 3 - 3x2 - 12x + 6x + 24 = 4x + 16Group the terms 2x - 12x + 6x - 3x2 + 3 + 24 = 4x + 16 Add/Subtract the terms -4x - 3x2 + 27 = 4x + 16Move all terms to one side 3x2 + 8x - 11 = 0

AO
Answered by Anya O. Maths tutor

3564 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand: (3x-1)(x+5)(4x-3)


Factorise fully x^3 - 10x^2 + 16x


Find the roots of the quadratic equation 2x^2 - 15x - 8


Show that (2x^2 + x -15)/(2x^3 +6x^2) * 6x^3/(2x^2 - 11x + 15) simplifies to ax/(x + b) where a and b are integers


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning