Simplify, leaving your answer as a quadratic: (2x + 3)/(x+4) - (3x - 6) = 4

(2x + 3)/(x+4) - (3x - 6) = 4 Initial equationTimes all terms by (x + 4) (2x + 3) - (3x - 6)(x + 4) = 4 (x + 4)Multiply out the brackets (2x + 3) - (3x2 + 12x - 6x - 24) = 4x + 16Remove from brackets by factoring in the minus sign 2x + 3 - 3x2 - 12x + 6x + 24 = 4x + 16Group the terms 2x - 12x + 6x - 3x2 + 3 + 24 = 4x + 16 Add/Subtract the terms -4x - 3x2 + 27 = 4x + 16Move all terms to one side 3x2 + 8x - 11 = 0

AO
Answered by Anya O. Maths tutor

3456 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise 3x^3y^2-6x^2y+9xy


Two simultaneous questions are given as 3x+2y = 9, and x-2y = -5. Find the values for x and y


Solve x^2 = 4(x – 3)^2


Differentiate dy/dx ((2x^3)+(x^2)-(4x)+7)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning