Solve the simultaneous equations 3x+2y=13 and 4x+y=14

Multiply the second equation by 2 so that the coefficients of y are equal.(4x+y=14) x2 = (8x+2y=28)Now subtract the first equation from 8x+2y=28.(8x+2y=28) - (3x+2y=13)and you get 5x=15.Divide both sides by 5.x=3Now substitute the value of x back into the second equation.4(3)+y=1412+y=14y=2