Factorize completely x^3 - 6x^2 + 11x - 6
Let f(x) = x^3 - 6x^2 + 11x - 6.
Try x = 1： f(1) = 1 - 6 + 11 - 6 = 0
So x - 1 is a factot of f(x).
Try x = 2： f(2) = 8 - 24 + 22 - 6 = 0
So x - 2 is a factot of f(x).
Try x = 3： f(3) = 27 - 54 + 33 - 6 = 0
So x - 3 is a factot of f(x).
Thus x^3 - 6x^2 + 11x - 6 = (x - 1)(x - 2)(x - 3)
KW
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