Solve (3x-2)/4 -(2x+5)/3 =(1-x)/6

The easiest way to solve this is to first eliminate the denominators by multiplying the whole expression by the lowest common multiple of 4, 3 and 6. In this case it is 12. If each fraction is multiplied by 12 then we get 3(3x-2)-4(2x+5)=2(1-x)Expanding the brackets gives 9x-6-8x-20=2-2xMoving all x terms to the LHS and all integers to the RHS: 9x-8x+2x=2+6+20Simplifying the expression: 3x=28dividing both sides by 3 gives the answer x=28/3 the value of x can be substituted into the original question to verify it is correct.