Solve the equation 3a^2+4a+1=3 for all values of a. Give your answers to 3 significant figures.

First take the 3 over the other side to make the right hand side zero, turning it into a homogeneous equation: 3a2+4a-2=0. Since the expression on the left hand side cannot be factorised, we have to use quadratic formula. Applying the quadratic formula gives the following solutions for a: a1= (-4 + sqrt(42 - (4 x 3 x -2)))/ (2 x 3) = (-4 + sqrt(40) / 6 = 0.3874... and a2= (-4 - sqrt(42 - (4 x 3 x -2)))/ (2 x 3) = (-4 - sqrt(40) / 6 = -1.7207... . Hence, final solutions are a = 0.387 and a = -1.72.

NA
Answered by Nida A. Maths tutor

3880 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

(x+2)(x-3) expand and simplify


Azmol, Ryan and Kim each played a game. Azmol’s score was four times Ryan’s score. Kim’s score was half of Azmol’s score. Write down the ratio of Azmol’s score to Ryan’s score to Kim’s score.


What is Pythagoras' theorem?


Find the inverse function of f(x)=5/(x-4)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning