Solve 8x + 9y = 3 and x + y = 0.

We have 8x + 9y = 3 [1] and x + y = 0 [2].We can make x or y the subject. Take y as subject we have y = -x [3].We substitute [3] into [1] and get 8x - 9x = 3 --> -x = 3 --> x = -3.Substituting x = -3 into [2] we get -3 + y = 0 --> y = 3.Final answer: x = -3 and y = 3.

TO

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 3x + 2y =4 4x + 5y =17


1. factorise x^2 - 9 Level 6 KS3, 2. Rearrange a (q-c) = d to make q the subject


How do you calculate arc length and sector area and why is it calculated like this? You are given sector angle 40 degrees and radius 7cm and asked to give answers to 3sf.


You are given sets A: {2,4,6,8,10,12} and B: {1,3,5,7,9,11} explain why A∩B = ∅