Solve the simultaneous equations: 3x+4y=19, x-6y= -23.

In order to solve these simultaneous equations we first want to eliminate one of the variables (x or y) and find a solution to the variable remaining (y or x) and then use this solution to find the second variable. To simplify this problem we want to make one of the variables in both equations equal, i.e. in this problem we can multiply the second equation by 3 to get 3x-18y= -69, rearranging this to get 3x on its own we get 3x= 18y-69. Rearranging the first equation to get 3x on its own yields 3x=19-4y. We can now equate these two equations as both are equal to 3x, hence 18y-69=19-4y, rearranging to solve for y gives 22y=88 and hence y=4. Substituting y=4 into one of the original equations to solve for x, (using the second equation) x= 6y-23=6*4-23=24-23=1. Hence the solutions are x=1 and y=4.

NL
Answered by Nathalie L. Maths tutor

3791 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: 3x+2y=4 and 4x+5y=17


What is the gradient and the y-intercept of the graph y = 3x + 7 ?


Prove that multiplication of two odd numbers produces an odd number.


Solve the simultaneous equations 3x + 2y = 4 and 4x + 5y = 17


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning