The perimeter of an isosceles triangle is 16cm. The length of the base of the triangle is x+4 and that of the other two sides is x+3. Find the area of the triangle
16=2(x+3)+(x+4)16=2x+6+x+46=3xx=2 - Therefore the base has length 6
a=6y/2 - where y is the perpendicular heighty^2=5^2-3^2y^2=25-9y^2=16y=4
Therefore a=(6*4)/2 a=12 cm^2
PF
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