How do I use the quadratic formula?

example quadratic eqn: ax2+bx+c=0 => x = (-b+-(b2-4ac)1/2)/2a e.g. 4x2-13x+3/4=0 x= (13+-(157)1/2)/8 = 3.1912, 0.0588

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Answered by Ben B. Maths tutor

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solve; (6x - 2)/2 - (4x+7)/3 = 1-x


A,B and C all lie on the line x^2 + y^2 = 49 where A is on the y axis, B is on the X axis and C is the mid point of the straight-line connecting A and B.


x^2 = 4(x – 3)^2


Re-arrange [4x+ 9t + 8s= 3g] to make x the subject of the formula


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