Solve the simultaneous equations. x^2 + 2y=9, y-x=3

Use the method of substitution to answer this question.
Step 1: Rearrange one of the equations to find x or y.
y-x=3 y=x+3
Step 2: Substitute your y into the first equation
x2+2y=9 x2+2(x+3)=9
Step 3: Expand the brackets and rearrange to form a quadratic equation
x2+2x+6=9 x2+2x-3=0
Step 4: Factorise the equation to find your values for x
(x+3)(x-1)=0Therefore x=-3 or x=1
Step 5: Find the corresponding y values
y=x+3when x=-3 y=0 and when x=1 y=4

KW
Answered by Kieran W. Maths tutor

4813 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations 3x+2y=13 and 4x+y=14


Prove algebraically that the straight line with equation x - 2y = 10 is a tangent to the circle with equation x^2 + y^2= 20


2x-4=6, find x.


A cuboid has dimensions: width = x+1, length = 2x-2, height = x+2. Work out the volume of this cuboid. Give your answer in terms of x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning