Make "a" the subject of the following equation: 2b = (3a+4)/(c-a)

In order to solve this question, we need to have all the terms containing 'a' on one side of the equals sign, and the other terms on the other side of the equals sign. First, we multiply both sides by (c-a), giving us:2b(c-a) = 3a+4,next we expand the left hand side:2bc-2ab = 3a+4,We now subtract 4 from both sides, and add 2ac:2bc-4 = 3a+2ab, next, we factorise the right hand side, and divide by whats in the brackets:(2bc-4)/(2b+3) = a,as required.