A curve is defined with the following parameters; x = 3 - 4t , y = 1 + 2/t . Find dy/dx in terms of x and y.

Using the chain rule, we know that dy/dx = dy/dt . dt/dx Therefore we differentiate both equations with respect to t:dx/dt = -4dy/dt = -2/(t^2)therefore dy/dx = -1/4 . -2/(t^2)dy/dx = 1/(2t^2) ... (we know that t = (3-x)/4 )therefore dy/dx = 8/((3-x)^2)

BA

Related Maths A Level answers

All answers ▸

let line L have the equation 4y -3x =10, and line M passes through the points (5,-1) and (-1,8), find out if they are perpendicular, parallel, or neither


How do I prove (x-2) is a factor of the function f(x) = x^2-4x+4?


How to find the angle between two 3-dimensional vectors:


Find tan(A-B) sec^2(A) - 2tan(A) = 16 && sin(B)sec^2(B) = 64cos(B)cosec^2(B)