A curve is defined with the following parameters; x = 3 - 4t , y = 1 + 2/t . Find dy/dx in terms of x and y.

Using the chain rule, we know that dy/dx = dy/dt . dt/dx Therefore we differentiate both equations with respect to t:dx/dt = -4dy/dt = -2/(t^2)therefore dy/dx = -1/4 . -2/(t^2)dy/dx = 1/(2t^2) ... (we know that t = (3-x)/4 )therefore dy/dx = 8/((3-x)^2)

BA
Answered by Brandon A. Maths tutor

3373 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that log_{x} (7y+1) - log_{x} (2y) =1 x>4, 0<y<1 , express y in terms of x.


Differentiate y = ln (3x + 2)


Expand using binomial expansion (1+6x)^3


Sketch y = 9x – 4x^3, showing where the curve crosses the x axis.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning