A curve is defined with the following parameters; x = 3 - 4t , y = 1 + 2/t . Find dy/dx in terms of x and y.

Using the chain rule, we know that dy/dx = dy/dt . dt/dx Therefore we differentiate both equations with respect to t:dx/dt = -4dy/dt = -2/(t^2)therefore dy/dx = -1/4 . -2/(t^2)dy/dx = 1/(2t^2) ... (we know that t = (3-x)/4 )therefore dy/dx = 8/((3-x)^2)

BA
Answered by Brandon A. Maths tutor

2964 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Can you prove to me why cos^2(X) + sin^2(X) = 1?


What is a moment and how do I calculate it?


Find the turning points of the curve y=2x^3 - 3x^2 - 14.


d/dx ( sin x) ^3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences