Find the value of roots of the quadratic: x^2-13x=30

First rearrange the equation so the LHS is equal to Zero:X2-13x-30=0Then find the factors of -30:-1,30/1,-30-2,15/2,-15-3,10/3,-10-6,5/6,-5Chose the factor pairs which add to equal -13which is 2 and -15.Create your bracket equation (x+2)(x-15)=0Test your bracket equation by expanding the brackets.To find the roots: either one brackets must equal to zero which can be written as"x+2=0 or x-15=0"then make X the subject of both equations to get your final answer:"x=-2 or x=15"

TZ

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations 5x+2y=13 and x-2y=5.


5x+3 = 18. What is the value of x?


Solve the Simultaneous equation: 6x+3y=13, 14x-9y=9?


How do I draw a pie diagram?