Solve, giving your answer to 3 s.f. : 2^(2x) - 6(2^(x) ) + 5 = 0

2^2x - 6(2^x ) + 5 = 0let y = 2^xy² - 6y + 5 = 0(y-5)(y-1) = 0 y=5, y=12^x = 5, therefore, x = log₂5 = 2.32 (3 s.f.)2^x = 1, therefore, x = log₂1 = 0