Solve, giving your answer to 3 s.f. : 2^(2x) - 6(2^(x) ) + 5 = 0
22x - 6(2x ) + 5 = 0let y = 2xy2 - 6y + 5 = 0(y-5)(y-1) = 0 y=5, y=12x = 5, therefore, x = log25 = 2.32 (3 s.f.)2x = 1, therefore, x = log21 = 0
JO
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