What are the two roots of the equation (4x-8)(x-3) = 0?
Since there are two terms multiplying together, when either of them are equal to zero, the total multiplication will also be zero. Ie, 10 x 0 = 0. This means that to find the two roots, we can simply equate each of the two multiplying terms to zero.4x - 8 = 0, and x - 3 = 0. Rearranging, we get x = 2, and x = 3. Therefore our two solutions are x = 2 and x = 3.
DD
Related Maths GCSE answers
All answers ▸If there are 20 marbles in a bag and 1/5 are red, what fraction are red if 1 more red marble is added?
complete the square by rewriting x^2+6x-15 in the form (x+p)^2-q
How do you translate the graph y = x^2, five unit squares negatively horizontally and 3 unit squares positively vertically?
A linear sequence starts: a+2b, a+6b, a+10b, ..., ... The 2nd term has a value of 8. The 5th term has a value of 44. Work out the values of a and b.