Two people sit opposite each other on the edge of a rotating disk of radius, R, and negligible mass. One person has a mass of 40kg, the other of 50kg. The disk is rotating at 30 revs/min. What is the rotational kinetic energy if R=1.5m?

Rotational Kinetic Energy (KE) = (1/2) x Moment of Inertia (I) x (Angular Velocity (w) )2I=SUM(MR2) = 40 x (1.5)2 + 50 x (1.5)2 = 90 x (1.5)2 = 202.5 kgm2w= 30 revs / min = 30 x (2π/60) = π (rad/s)KE= 0.5 x 202.5 x π2 = 101.25 π2
KE= 999.297.... ~ 1000J

Answered by Joe S. Physics tutor

1127 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A 4 metre long bar rotates freely around a central pivot. 3 forces act upon it: 7N down, 2m to the left of the pivot; 8N up, 1m to the left of the pivot; 4N up, 1m to the right of the pivot. Apply one additional force to place the bar in equilibrium.


If a vehicle A, 1000kg moving at 5m/s collides with vehicle B, 750kg, moving in the opposite direction at 8m/s assuming no rebound what is the velocity of the vehicles after collision.


What speed do satellites orbit at?


What is damping in Simple Harmonic Motion?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy