Given that y = x^2 +2x + 3, find dy/dx.
We use a typical rule for polynomials in the form y = axb , where a and b are real numbers. Also, for a polynomial equation y = axb +cxd +.... , dy/dx = d( axb)/dx + d(cxd)/dx + ...With this information, we can differentiate y = x2 +2x + 3 :dy/dx = d(x2)/dx + d(2x)/dx + d(3)/dx = 2x1 + 2x0 + 0x-1 = 2x + 2.
JC
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