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Differentiate with respect to x and write in its simpliest form, Y=(2x-3)/x^2?

Y=(2x-3)/x2

Quotient Rule: dY/dx(u/v)=(u'v-v'u)/v2

dY/dx=(2x2-2x(2x-3))/x4

=(6x-2x2)/x4    (Collect numerator x terms.)

=(6-2x)/x3         (Cancel the fraction by a factor of x.)

dY/dx=(6-2x)/x3

JD

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