Differentiate with respect to x and write in its simpliest form, Y=(2x-3)/x^2?
Y=(2x-3)/x2
Quotient Rule: dY/dx(u/v)=(u'v-v'u)/v2
dY/dx=(2x2-2x(2x-3))/x4
=(6x-2x2)/x4 (Collect numerator x terms.)
=(6-2x)/x3 (Cancel the fraction by a factor of x.)
dY/dx=(6-2x)/x3
JD
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